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8m^2+54m-14=0
a = 8; b = 54; c = -14;
Δ = b2-4ac
Δ = 542-4·8·(-14)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3364}=58$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-58}{2*8}=\frac{-112}{16} =-7 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+58}{2*8}=\frac{4}{16} =1/4 $
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